5x^-4/3y^0

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Solution for 5x^-4/3y^0 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

y^0*((5*x^-4)/3) = 0

(5*x^-4)/3 = 0

5/3*x^-4 = 0 // : 5/3

x^-4 = 0

x należy do O

x belongs to the empty set

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